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A rod of length (f/2) is placed along th...

A rod of length (f/2) is placed along the axis of a concave mirror of focal length f. If the near ead of the real image formed by the mirror just touches the far end of the rod, find its magnification.

Text Solution

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(i) Draw a ray diagram representing the given situation.
Let AB be the object and A be the near end of the object and B be the far end of the object.
Let A'B' be the image formed.
As B' coincides with the end B at the centre of curvature,
`:. ` the distance of B from the mirror = 2f.
Let the length of the object be `f/2`.
The end A is at a distance of `(2f-f/2)`.
By using `1/f = 1/v - 1/u`,
Determine the distance of A'B', from the mirror and find the length of the image. u= 2f - d
The magnification , `m = ("length of the image")/("length of the object") `
(ii) m = 2
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