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Find the electric field strength due to `5 mu C` of charge at point 30 m away from it in air.

Text Solution

Verified by Experts

Given `Q = 5 muC = (5 xx 10^(-6)C)`
`r = 30 m`
`:.` The electric field strength `E = 1/(4pi in_(0)) = (Q)/(r^(2)) = 9 xx 10^(9) ((5 xx 10^(-6))/((30)^(2))) = 50 N C^(-1)`.
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