Calculate the work done to move `500 xx 10^(18)`, electrons between two points in an electric field where the potential difference between the two point is 1 millivolt `(e = 1.6 xx 10^(-19)C)`

Explanation

The number of electrons, `n = 500 xx 10^(18)`
The charge of each electron, `e = 1.6 xx 10^(-19) C`.
`:.` The total energy charge, `q = "ne" = 500 xx 10^(18) xx 1.6 xx 10^(-19) = 80 C`
The potential difference between the two points,
`Delta V = 1` millivolt `=10^(-3)V`
`:.` Work done `w = DeltaVq = 10^(-3) xx 80 = 0.08 J`.