A stream of electrons with kinetic energy equal to 100 keV pass across a cross setion of a conductor in `0.5 s`. If the potential difference between the ends of conductor is 5 V find the number of electrons that pass across the conductor in one second. (The charge on an electron is `1.6 xx 10^(-19)C`).

Explanation

(i) Use the formula, `P.D., V = w/q`
`V = (KE)/("ne")`
(since, `q = "ne"`)
Find the value of 'n' from (1)
This many numberof electrons pass in `0.5` second.
Double this number of electrons passes across the conductor in one second.
(ii) `4 xx 10^(4)` electrons.