For a particle performing `SHM`, equation of motion is given as `(d^(2))/(dt^(2)) + 4x = 0`. Find the time period

For a particle performing SHM , equation of motion is given as (d^(2))/(dt^(2)) + 9x = 0 . Find the time period

Differential equation for a particle performing linear SHM is given by (d^(2)x)/(dt^(2))+3xx=0 , where x is the displacement of the particle. The frequency of oscillatory motion is

If a simple harmonic motion is represented by (d^(2)x)/(dt^(2)) + alphax = 0 , its time period is :

If a simple harmonic motion is represented by (d^(2)x)/(dt^(2)) + alphax = 0 , its time period is :

If a simple harmonic motion is represented by (d^(2)x)/(dt^(2)) + alphax = 0 , its time period is :

The equation of simple harmonic motion of a source is (d^2x)/(dt^2)+px=0 , find the time period.

If a simple harmonic motion is erpresented by (d^(2)x)/(dt^(2))+ax=0 , its time period is.

If a simple harmonic motion is represented by (d^(2)x)/(dt^(2))+αx=0 , its time period is.

Passage XI) The differential equation of a particle undergoing SHM is given by a(d^(2)x)/(dt^(2)) +bx = 0. The particle starts from the extreme position. The ratio of the maximum acceleration to the maximum velocity of the particle is