A person hears the sound of explosion of a bomb after 5 s. If the velocity of sound in air is `330 ms^(-1)`, the distance between the bomb and the person is ____ km.

Options

A. `1`
B. `1.65`
C. `2.35`
D. `330`

Explanation

To solve the problem, we need to find the distance between the bomb and the person using the given information about the time it takes for the sound to reach the person and the speed of sound in air.

### Step-by-step Solution:

1. **Identify the given values:**
- Time taken for sound to reach the person (t) = 5 seconds
- Velocity of sound in air (v) = 330 m/s

2. **Use the formula for distance:**
The formula to calculate distance (d) when speed and time are known is:
\[ d = v \times t \]

3. **Substitute the values into the formula:**
\[ d = 330 \, \text{m/s} \times 5 \, \text{s} \]

4. **Calculate the distance in meters:**
\[ d = 1650 \, \text{m} \]

5. **Convert the distance from meters to kilometers:**
Since 1 kilometer = 1000 meters, we convert the distance:
\[ d = \frac{1650 \, \text{m}}{1000} = 1.65 \, \text{km} \]

6. **Final answer:**
The distance between the bomb and the person is **1.65 km**.