A police targets a thief, who is at rest at point Q. He fires a bullet from a point P which is at a distance of 990 m from Q and it reaches the point Q in 3 s. When the bullet is fired at P it produced a sound, which was heard by the theif. What is the difference in time taken by the sound and the bullet to reach point Q. Will the thief be able to escape from the bullet fired by police ? Take the velocity of sound in air as `330 ms^(-1)`.

Explanation

Distance between points P and Q, (d) = 990 m.
Time, (t) = 3 s.
Speed with which the bullet moves is
`= (990 m)/(3s) = 330 ms^(-1)`.
As the speed of body matches the speed of sound, the time interval is zero. The thief cannot escape the bullet.