In the above example, the velocity after 2 sec will be - (in m/sec)

The velocity v m/sec of particle is proportional to the cube of the time. If the velocity after 2 secs is 4m/sec, then v is equal to :

In the above problem the velocity of the centre of mass after 1 sec will be :

A body moves according to the formula v=l+t^2 , where V is the velocity at time t. The acceleration after 3sec will be ( v in cm//sec ) a) 24cm//sec^2 b) 12cm//sec^2 c) 6cm//sec^2 d)None of these

A particle moves on a line according to the law s=at^(2)+bt+c . If the displacement after 1 sec is 16 cm, the velocity after 2 sec is 24 cm/sec and acceleration is 8cm//sec^(2) , then

A particle moves on a line according to the law s=at^(2)+bt+c . If the displacement after 1 sec is 16 cm, the velocity after 2 sec is 24 cm/sec and acceleration is 8cm//sec^(2) , then

A body moves according to the formula v=l+t^2 , where V is the velocity at time t. The acceleration after 3sec will be ( v in cm//sec )

A car is moving in a circular path of radius 100 m with velocity of 200 m/sec such that in each sec its velocity increases by 100 m/s, the net acceleration of car will be - (in m/sec)

A car is moving in a circular path of radius 100 m with velocity of 200 m/sec such that in each sec its velocity increases by 100 m/s, the net acceleration of car will be - (in m/sec)

What is the velocity at 4 sec, if velocity at = 0 is 8m/s