For the raction
`B_(2)H_(6)(g)+3O_(2)(g)rarrB_(2)O_(2)(s)+3H_(2)O(l)`
`DeltaE=-2143.2KJ`
Calculate `DeltaH` for the reaction at `25^(@)C`

For the reaction C_(2)H_(4)(g)+3O_(2)(g) rarr 2CO_(2) (g) +2H_(2)O(l) , Delta E=-1415 kJ . The DeltaH at 27^(@)C is

Diborane is a potentail rocket fuel which undergoes combusion according to the reaction B_(2)H_(6)(g)+3O_(2)(g)rarrB_(2)O_(3)(s)+3H_(2)O(g) From the following data, calculate the enthalpy change for the combustion of diborane 2B(s)+(3//2)O_(2)(g)rarrB_(2)O_(3)(s) DeltaH= -1273 kJ mol^(-1) H_(2)(g)+(1//2)O_(2)(g)rarrH_(2)O(1) " "Delta H= -286 kJ mol^(-1) H_(2)O(1)rarrH_(2)O(g)" "DeltaH=44 kJ mol^(-1) 2B(s)+3H_(2)(g)rarrB_(2)H_(6)(g)" "Delta H= 36kJ mol^(-1)

Diborane is a potentail rocket fuel which undergoes combusion according to the reaction B_(2)H_(6)(g)+3O_(2)(g)rarrB_(2)O_(3)(s)+3H_(2)O(g) From the following data, calculate the enthalpy change for the combustion of diborane 2B(s)+(3//2)O_(2)(g)rarrB_(2)O_(3)(s) DeltaH= -1273 kJ mol^(-1) H_(2)(g)+(1//2)O_(2)(g)rarrH_(2)O(1) " "Delta H= -286 kJ mol^(-1) H_(2)O(1)rarrH_(2)O(g)" "DeltaH=44 kJ mol^(-1) 2B(s)+3H_(2)(g)rarrB_(2)H_(6)(g)" "Delta H= 36kJ mol^(-1)

Diborane is a potential rocket fuel which undergoes combustion according to the reaction, B_(2)H_(6) (g) + 3O_(2) (g) rarr B_(2) O_(3) (s) + 3H_(2) O (g) From the following data, calculate the enthalpy change for the combustion of diborane: (i) 2 B (s) + ((3)/(2)) O_(2) (g) rarr B_(2) O_(3) (s) , Delta H = 0 1273 k J//mol (ii) H_(2) (g) + ((1)/(2)) O_(2) (g) rarr H_(2) O (l), Delta H = -286 kJ//mol (iii) H_(2) O (l) rarr H_(2)O (g) Delta H = 44 kJ//mol (iv) 2B (s) + 3H_(2) (G) rarr B_(2) H_(6) (g), Delta H = 36 kJ//mol

Diborane is a potential rocket fuel which undergoes combustion according to the reaction, B_(2)H_(6)(g)+3O_(2)(g)toB_(2)O_(3)(s)+3H_(2)O(g) from the following data, the enthalpy change for the combustion of diborane will be : 2B(s)+(3)/(2)O_(2)(g)toB_(2)O_(3)(s)," "DeltaH=-1273 " kJ" H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(l)," "DeltaH=-286 " kJ" H_(2)O(l)toH_(2)O(g)," "DeltaH=44" kJ" 2B(s)+3H_(2)(g)toB_(2)H_(6)(g)," "DeltaH=46" kJ"

If 2AI(s) +1(1)/(2) O_(2)(g) rarr AI_(2)O_(3)(s), DeltaH =- 1667.8 kJ H_(2)(g) +(1)/(2)O_(2)(g) rarr H_(2)O(l), DeltaH =- 285.9 kJ Calculate DeltaH for the reaction AI_(2)O_(3)(s) rarr 2AI(s) +1(1)/(2)O_(2)(g)