Young's modulus of rubber is `10^(4) N//m^(2)` and area of cross section is `2 cm^(-2)`. If force of `2 xx 10^(5) dyn` is applied along its length, then its initial l becomes

Young's modulus of rubber is 10^(4) N//m^(2) and area of cross section is 2 cm^(2) . If force of 2 xx 10^(5) dyn is applied along its length, then its final length becomes

The Young's modulus of a wire of length 2m and area of cross section 1 mm^(2) is 2 xx 10^(11) N//m^(2) . The work done in increasing its length by 2mm is

The young's modulus of a wire of length 2m and area of cross section 1mm^2 is 2 xx 10^10 N/m^2 . What is the work done in increasing it's length by 2mm.

Young modulus of elasticity of brass is 10^(11)N//m^(2) . On pressing the rod of length 0.1 m. and cross section area 1 cm^(2) made from brass with a force of 10 N. along its length, the increase in its energy will be……………………

A 20 N stone is suspended from a wire and its length changes by 1% . If the Young's modulus of the material of wire is 2xx10^(11)N//m^(2) , then the area of cross-section of the wire is 2xx10^(11)N//m^(2) , then the area of cross-section of the wire will be

The Young's modulus of a material having a cross-sectional area of 1cm^(2) is 2 xx 10^(12)"dyne/cm"^(2) . If the length is to be doubled the force required is

The length of a rod is 20 cm and area of cross-section 2 cm^(2) . The Young's modulus of the material of wire is 1.4 xx 10^(11) N//m^(2) . If the rod is compressed by 5 kg-wt along its length, then increase in the energy of the rod in joules will be