The adjoining figure shows a disc of mass M and radius R lying in the X-Y plane with its centre on X - axis at a distance a from the origin. Then the moment of inertia of the disc about the X-axis is

A uniform disc (of mass M and radius a ) has a hole (of radius b ) drilled through it. The centre of the hole is at a distance c from the centre of the original disc. What is the moment of inertia of the disc about an axis through the centre of the disc and perpendicular to its plane ?

A uniform circular disc of radius R lies in the XY plane with its centre coinciding with the origin.The moment of inertia about an axis passing through a point on the X-axis at a distance x=2R and perpendicular to the X-Y plane is equal to its moment of inertia about an axis passing through a pint on the Y-axis at a distance y=d and parallel to the X-axis in the X-Y plane. The value of d is

If the radius of gyration of a solid disc of mass 10 kg about an axis is 0.40 m, then the moment of inertia of the disc about that axis is

The moment of inertia of a disc of mass M and radius R about a tangent to its rim in its plane is

A solid sphere of mass M and radius R having moment of inertial I about its diameter is recast into a solid disc of radius r and thickness t .The moment of inertia of the disc about an axis passing the edge and perpendicular to the plane remains "I" .Then r=(x)/(sqrt(15))R Find x=?

Moment of inertia of a disc about an axis parallel to diameter and at a distance x from the centre of the disc is same as the moment of inertia of the disc about its centre axis. The radius of disc is R . The value of x is

A thin disc of mass 9M and radius R from which a disc of radius R/3 is cut shown in figure. Then moment of inertia of the remaining disc about O, perpendicular to the plane of disc is -

A small hole is made in a disc of mass M and radius R at a distance R//4 from centre. The disc is supported on a horizontal peg through this hole. The moment of inertia of the disc about horizontal peg is

A uniform disc of radius R lies in the x-y plane, with its centre at origin. Its moment of inertia about z-axis is equal to its moment of inertia about line y = x + c . The value of c will be. .

The moment of inertia of a uniform circular disc of mass M and radius R about any of its diameters is 1/4 MR^(2) . What is the moment of inertia of the disc about an axis passing through its centre and normal to the disc?