In figure, block A is released from rest, when spring is at its natural unstretched length. For block B of mass M to leave contact with the ground at some stage, the minimum mass of A must be

In the adjoining diagram the ball A is released from rest when the spring is at its natural length (neither stretched nor compressed) For the block B of mass M to leave contact with the ground at some time, the minimum mass of A must be:

In the arrangement shown in the fig. string, springs and the pulley are mass less. Both the springs have a force constant of k and the mass of block B resting on the table is M. Ball A is released from rest when both the springs are in natural length and just taut. Find the minimum value of mass of A so that block B leaves contact with the table at some stage

In the arrangement shown in the figure, block B of mass M rests on a weighing scale. Ball A is released from a position where spring is in its natural length and the scale shows the correct weight of block B. Find the mass of ball A so that the minimum reading shown by the scale subsequently is half the true weight of B.

Block m is released from rest when spring is in its natural length ( assume pulley is ideal and block does not strike on ground during it's motion in vertical plane ) than :

System shown in figure is released from rest . Pulley and spring is massless and friction is absent everywhere. The speed of 5 kg block when 2 kg block leaves the contact with ground is (force constant of spring k = 40 N//m and g = 10 m//s^(2))

The block shown in figure is released from rest and initially the spring is at its natural length. Write down the energy conservation equation. When the spring is compressed by l_(1) ?

The block of mass m is released when the spring was in its natrual length. Spring constant is k. Find the maximum elongation of the spring.

The system is released from rest with spring intially in its natural length. If mass of the block m = 10 kg. and spring constant k = 100 N//m , then maximum extension in spring is :