For the ellipse `((x-2)^(2))/(16)+(y^(2))/(12)=1`. A is any point on it and B,C are its foci then AB+AC

The foci of the ellipse ((x-3)^(2))/(36)+((y+2)^(2))/(16)=1, are

The foci of the ellipse (x^(2))/(4) +(y^(2))/(25) = 1 are :

If SandS are the foci of the ellipse (x^(2))/(25)+(y^(2))/(16)=1, and P is any point on it,then the range of values of SPS'P is (a) 9<=f(theta)<=16( b) 9<=f(theta)<=25 (c) 16<=f(theta)<=25 (d) 1<=f(theta)<=16

P is any point on the ellipise (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 and S and S are its foci, then maximum value of the angle SPS is

If M_(1) and M_(2) are the feet of perpendiculars from foci F_(1) and F_(2) of the ellipse (x^(2))/(64)+(y^(2))/(25)=1 on the tangent at any point P of the ellipse then

Foci of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1(alt b) are

The straight line (x)/(4)+(y)/(3)=1 intersects the ellipse (x^(2))/(16)+(y^(2))/(9)=1 at two points A and B there is a point P on this ellipse such that the area of Delta PAB is equal to 6(sqrt(2)-1) . Then the number of such point (P) is/are (A) 4 (B) 1 (C) 2 (D) 3

The product of the perpendiculars from the two foci of the ellipse (x^(2))/(9)+(y^(2))/(25)=1 on the tangent at any point on the ellipse