The centre of circle cutting the three circles`x^(2)+y^(2)-4x-4y+5=0`,`x^(2)+y^(2)-4x-6y+5=0`,`x^(2)+y^(2)-4x-8y+5=0` orthogonally is

The equation of the circle which cuts the three circles x^(2)+y^(2)-4x-6y+4=0 , x^(2)+y^(2)-2x-8y+4=0 and x^(2)+y^(2)-6x-6y+4=0 orthogonally is

The equation of a circle which cuts the three circles x^(2)+y^(2)+2x+4y+1=0,x^(2)+y^(2)-x-4y+8=0 and x^(2)+y^(2)+2x-6y+9=0 orthogonlly is

Find the equation of the circle which cuts the three circles x^(2)+y^(2)-3x-6y+14=0,x^(2)+y^(2)-x-4y+8=0 and x^(2)+y^(2)+2x-6y+9=0 orthogonally.

The radical center of the circles x^(2)+y^(2)-4x-6y+5=0 , x^(2)+y^(2)-2x-4y-1=0 , x^(2)+y^(2)-6x-2y=0 .

The angle between the circles x^(2)+y^(2)-4x-6y-3=0 ,x^(2)+y^(2)+8x-4y+11=0

The angle between the circles x^(2)+y^(2)-4x-6y-3=0 ,x^(2)+y^(2)+8x-4y+11=0

The angle between the circles x^(2)+y^(2)-4x-6y-3=0 , x^(2)+y^(2)+8x-4y+11=0