A normal to the hyperbola, `4x^2_9y^2 = 36` meets the co-ordinate axes `x` and `y` at `A` and `B.` respectively. If the parallelogram `OABP (O` being the origin) is formed, then the locus of `P` is :-

Tangents at any point on the hyperbola (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 cut the axes at A and B respectively,If the rectangle at OAPB (where O is origin) is completed then locus of point P is given by

If the normal to the rectangular hyperbola x^(2) - y^(2) = 4 at a point P meets the coordinates axes in Q and R and O is the centre of the hyperbola , then

If the normal at P to the rectangular hyperbola x^(2) - y^(2) = 4 meets the axes of x and y in G and g respectively and C is the centre of the hyperbola, then 2PC =

Ifthe normal at P the rectangular hyperbola x^(2)-y^(2)=4 meets the axes in G and g and C is the centre of the hyperbola,then

In the hyperbola 4x^2 - 9y^2 = 36 , find the axes, the coordinates of the foci, the eccentricity, and the latus rectum.