If the mass of a proton,`m_(p)=1.008u`mass of a neutron `m_(n)=1.009u`,then the binding energy of an `alpha` -particle of mass `4.003` u will be (Mev) (take 1a.m.u=931MeV)

If the mass of proton= 1.008 a.m.u. and mass of neutron=1.009a.m.u. then binding energy per nucleon for ._(4)Be^9 (mass=9.012 amu) would be-

The binding energy of alpha -particle is ( if m_p=1.00785u , m_n=1.00866u and m_alpha=4.00274u )

The mass of proton is 1.0073 u and that of neutron is 1.0087 u ( u=atomic mass unit ). The binding energy of ._2^4He , if mass of ._2^4He is 4.0015 u is

The masses of neutron and proton are 1.0087 a.m.u. and 1.0073 a.m.u. respectively. If the neutrons and protons combine to form a helium nucleus (alpha particle) of mass 4.0015 a.m.u. The binding energy of the helium nucleus will be (1 a.m.u. = 931 MeV) .

The atomic mass of F^(19) is 18.9984 m_(u) . If the masses of proton and neutron are 1.0078 m_(u) and .0087 m_(u) . Respectively, calculate the binding energy per nucleon (ignore the mass of electrons). (1 m_(u) = 931) MeV)

The mass of proton is 1.0073 u and that of neutron is 1.0087 u ( u= atomic mass unit). The binding energy of ._(2)He^(4) is (mass of helium nucleus =4.0015 u )

The masses of neutron and proton are 1.0087 a.m.u. and 1.0073 a.m.u. respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 a.m.u. The binding energy of the helium nucleus will be (1 a.m.u.= 931 MeV)

Find the Binding energy per neucleon for ""_(50)^(120)Sn Mass of proton m_(p)=1.00783U , mass of neutron m_(n)=1.00867U and mass of tin nucleus m_(Sn)=119.902199U . (take 1 U = 931 MEV)

If the mass defect of ""_(4)^(9)X is 0.09 a.m.u. then the binding energy per nucleon is (1 a.m.u= 931.5 MeV)

The bombardment of Lithium with protons gives rise to the following reaction: ._3Li^7+._1H^1 to .2_He^4+.2_He^4+Q The atomic masses of lithium, hydrogen and helium are : 7.016u, 1.008u and 4.004u resp. Find the initial energy of each of alpha particle. Take 1a.m.u=931MeV .