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The sum sum(x=2)^(44)2sin x*sin1[1+sec(x...

The sum `sum_(x=2)^(44)2sin x*sin1[1+sec(x-1)*sec(x+1)]` can be written in the form of `sum_(n=1)^(4)(-1)^(n)(phi^(2)(theta_(n)))/(psi(theta_(n))),` Where `theta` and `Psi` are trigonometric functions and `theta_(1),theta_(2),theta_(3),theta_(4)in[0,45].` If `(theta_(1)+theta_(2)+theta_(3)+theta_(4))` is a two digit natural number,then the non negative difference of digits of this number is.

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