Percentage of total distance covered in 5^(th) second by a freely falling body is

For a freely falling body

The KE of a freely falling body

What is a freely falling body ?

The distance travelled by a freely falling body is proportional to

In the previous problem, distance covered in the 7^(th) second is

Find the ratio of the distances travelled by a freely falling body in first, second and third second of its fall.

With what velocity a ball be projected vertically so that the distance covered by it in 5^(th) second is twice the distance it covers in its 6^(th) second (g=10 m//s^(2))