If the planes `2x-y-3z-7=0` and `4x-2y+5kz+9=0` are parallel then `5k^(2)+6`=

Show that the planes 2x-2y+4z+5=0 and 3x-3y+6z-1=0 are parallel.

The sum of the intercepts of the plane on the coordinate axes, passing through the intersection of the planes 2x+3y+3z-5=0 and 2x-5y+3z+1=0 and parallel to the line (x-1)/(2)=(y-2)/(-5)=(z-3)/(-7) , is

If the planes 2x+y-2z=0and x+2y+kz=0 are at right angles, then the value of k is

Find the equation of the plane through the intersection of the planes 3x-4y+5z=10 and 2x+2y-3z=4 and parallel to the line x=2y=3z

Two planes 5x-2y+4z+1=0 and 2x+y-kz=7 are orthogonal then k

If the planes 3x-2y+2z+17=0 and 4x+3y-kz=25 are mutually perpendicular , then k=

The equation of the plane passing through the intersection of the planes 2x-5y+z=3 and x+y+4z=5 and parallel to the plane x+3y+6z=1 is x+3y+6z=k , where k is

If the planes 2x-y+lamdaz-5=0 an x+4y+2z-7=0 are perpendicular then lamda=

The planes 2x - y + 4z = 3 and 5x - 2.5y + 10z = 6 are :