If `theta` is parameter,`A=(a cos theta,a sin theta)` and `B=(b sin theta,-b cos theta)C=(1,0)`then the locus of the centroid of `Delta ABC`

what is the relation between a cos theta+b sin theta=p and a sin theta-b cos theta=q

if theta is a parameter then x=a ( sin theta + cos theta), y=b( sin theta - cos theta ) respresents

The distance between the points (a cos theta+b sin theta,0) and (0,a sin theta-b cos theta)

a cos theta+b sin theta+c=0a cos theta+b_(1)sin theta+c_(1)=0

Let A(sin theta,cos theta-sin theta),B(cos theta+sin theta,-cos theta),C(cos theta+sin theta,cos theta-sin theta) and the locus of centroid of Delta ABC, where theta is a parameter is given by (x-2y)^(2)+(px+qy)^(2)=(49)/(9) then the value of product pq equals

If A(cos theta, sin theta), B (sin theta, cos theta), C (1, 2) are the vertices of DeltaABC . Find the locus of its centroid if theta varies.