A projectile is thrown horizontally with a speed of `20ms^(-1)` .If g is `(10ms^(-2))` ,then the speed of the projectile after 5 second will be nearly

A projectile is fired horizontally with an initial speed of 20 m/s/ its horzontal speed 3 sec later is:

From the top of a hill 480 m high , a projectile is fired horizontally with a speed of 96 m//s . Calculate (i) the time taken by projectile to reach the ground . (ii) the distance of the target from the hill . (iii) the velocity with which the projectile hits the ground . Take g=10ms^(-2)

A body is projected at an angle of 30^(@) with the horizontal and with a speed of 30ms^(-1) . What is the angle with the horizontal after 1.5 second? (g=10ms^(-2))

A body is projected horizontally with speed 20 ms^(-1) . The speed of the body after 5s is nearly

A body is projected at an angle of 30^@ with the horizontal and with a speed of 30 ms^-1 . What is the angle with the horizontal after 1.5 s ? (g = 10 ms^-2) .

A light body is projected with a velocity (10hat(i)+20 hat(j)+20 hat(k)) ms^(-1) . Wind blows along X-axis with an acceleration of 2.5 ms^(2) . If Y-axis is vertical then the speed of particle after 2 second will be (g=10 ms^(2))

A projectile is thrown with speed 40 ms^(-1) at angle theta from horizontal . It is found that projectile is at same height at 1s and 3s. What is the angle of projection ?

A projectile fired from a planet with a speed of 2ms^(-1) traces the same trajectory as the projectile fired from the earth at a speed of 4ms^(-1) .The acceleration due to gravity on the planet is?

Find time of flight if projectile thrown horizontally with speed 10 ms^(-1) from a long inclined plane which makes an angle of theta = 45^(@) from horizontal.