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If one root of x^(2)-(3+2i)x+(1+3i)=0 i...

If one root of `x^(2)-(3+2i)x+(1+3i)=0` is `1+i` then the other root is
A) `1-i`
B) `2+i`
C) `3+i`
D) `1+3i`

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Conjugate of ((1+i)(1+2i))/((1+3i))