Home
Class 11
MATHS
The equation of the locus of points whi...

The equation of the locus of points which are equidistant from the points (2,-3) and (3,-2) is
(A) x+y=0
(B) x+y=7
(C) 4x+4y=38
(D) x+y=1

Promotional Banner

Similar Questions

Explore conceptually related problems

The point on the line 4x-y-2=0 which is equidistant from the points (-5,6) and (3,2) is

If point (x,y) is equidistant from points (7,1) and (3,5) show that y=x-2

If the point (x, y) is equidistant from points (7, 1) and (3, 5) , find x-y.

If the points (2,1) and (1,-2) are equidistant from the point (x,y), show that x+3y=0

The equation of the tangent to the parabola y^2 = 9x which goes through the point (4, 10) is (A) x+4y+1=0 (B) 9x+4y+4=0 (C) x-4y+36=0 (D) 9x-4y+4=0

If the point (x, y) is equidistant from the points (2, 3) and (6, -1) , find the relation between x and y .

The point on the line 2x-3y=5 which is equidistant from (1,2) and (3,4) is