A particle is projected with velocity u ...

A particle is projected with velocity u at angle `theta_(1)` with horizontal .The ratio of range and maximum height is 4. When it is projected at angle `theta_(2)` with horizontal with same speed,the ratio of range and maximum height is 2.Then `(tan theta_(1))/(tan theta_(2))` will be equal to

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A particle is projected with velocity u at angle `theta_(1)` with horizontal .The ratio of range and maximum height is 4. When it is projected at angle `theta_(2)` with horizontal with same speed,the ratio of range and maximum height is 2.Then `(tan theta_(1))/(tan theta_(2))` will be equal to

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