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A particle is projected with velocity u at angle `theta_(1)` with horizontal .The ratio of range and maximum height is 4. When it is projected at angle `theta_(2)` with horizontal with same speed,the ratio of range and maximum height is 2.Then `(tan theta_(1))/(tan theta_(2))` will be equal to

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Knowledge Check

  • A particle is projected at t=0 with velocity u at angle theta with the horizontal. Then the ratio of the tangential acceleration and the radius of curvature at the point of projection is:

    A
    `(g^(2)sin2 theta)/(u^(2))`
    B
    `(2g^(2)sin theta)/(u^(2))`
    C
    `(g^(2)sin theta)/(u^(2))`
    D
    `(g^(2)sin 2 theta)/(2u^(2))`

  • A particle projected with velocity u at angle theta with horizontal at t=0. What is the magnitude of change in the velocity of the particle when it is at maximum height?

    A
    `(u cos theta)/2`
    B
    `u cos theta`
    C
    `u sin theta`
    D
    none of these

  • A psrticle is projected at t = 0 with velocity u at angle theta with the horizontal. Then the ratio of the tangential acceleration and the radius of curvature at the point of projection is :

    A
    `(g^(2)sin2theta)/(u^(2))`
    B
    `(2g^(2)sin theta)/(u^(2))`
    C
    `(g^(2)sin theta)/(u^(2))`
    D
    `(g^(2)sin 2theta)/(2u^(2))`

    • Similar Questions

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    A projectile is projected with a speed u at an angle theta with the horizontal. What is the speed when its direction of motion makes an angle theta//2 with the horizontal

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