A particle with the potential energy shown in the graph is moving to the right. It has 1.0J of kinetic energy at x=1.0m. Where the particle reverses its direction of motion?

A particle with the potentila energy shown in the graph is moving to the right. It has 1.0J of kinetic energy at x=1.0m. Where the particle reverses its direction of motion?

A particle with total energy E moves in one direction in a region where, the potential energy is U The acceleration of the particle is zero, where,

A particle with total energy E moves in one dimemsional region where the potential energy is U(x) The speed of the particle is zero where

A single conservative force F(x) acts on a particle that moves along the x - axis. The graph of the potential energy with x is given. At x=5m, the particle has a kinetic energy of 50 J and its potential energy is related to position 'x' as U=15+(x-3)^(2) Joule where x is in meter. Then:

A particle moves along x-axis whose potential energy versus x-coordinate graph is shown in the given figure. At x = 0, the particle is released form rest. Two potential wells A and B are shown in the figure. Then,

A particle of mass m moves in the potential energy U shoen above. The period of the motion when the particle has total energy E is

At time t , the kinetic energy of a particle is 30.0J and the potential energy of the system to which it belongs is 10.0J . At some later time t_f , the kinetic energy of the particle is 18J , what are the potential energy and the total energy at time t_f ? If the potential energy of the system at time t_3 is 5.00J , are any non-conservative forces acting on the particle? Explain.

A particle with total energy E is moving in a potential energy region U(x). Motion of the particle is restricted to the region when