Let `a=min{x^(2)+2x+3,x in R}` and `b=lim_(xto0)(64)/(x^(4))[1-cos(x/2)-cos(x/4)+cos(x/2)cos(x/4)]` then

" Let "a=min{x^(2)+2x+3,x in R}" and ", b=Lt_(x rarr0)(64)/(x^(4))[1-cos(x/2)-cos(x/4)+cos(x/2)cos(x/4)] then find the value of a and b

lim_(xto0) (1)/(x^12){1-cos (x^2/2)-cos (x^4/4)+cos (x^2/2) cos (x^4/4)} is equal to

lim_(x rarr0)(1-(x^(2))/(2)-cos(x))/(x^(4))

lim_(x rarr0)(sin^(2)4x+2cos^(2)x-2cos x)/(cos^(2)x-cos^(3)x)

lim_(x rarr0)(x(5^(x)-3^(x)))/(cos2x-cos4x)

lim_(x to 0) (cos 2x-1)/(cos x-1)

Find lim_(xto0) sqrt((1)/(2)(1-cos2x))/(x) if exists.

lim_(x->0)(1-cos x-cos2x+cos x*cos2x)/(x^(4))