0.037g of an alcohol, R-OH was added to `CH_(3)MgBr` and the gas evolved measured 11.2 mL at STP. The Molecular mass of R-OH will be .

0.037gm of an alcohol was added to CH_(3)Mgl and the gas evolved measured 11.2ml at STP . What is the molecular weight of the alcohol ? Identify (A) to (E) .

0.2 g of a primary aliphatic amine, on treatment with nitrous acid gave 61.36 ml of N_2 gas at STP. The molecular mass of the amine will be:

The treatment of CH_(3)OH "with" CH_(3)Mgl releases 1.04mL of a gas at STP. The mass of CH_(3)OH added is

A sample of 6.75mg of unknown alcohol is added to CH_(3)MgBr when 2.52ml of CH_(4) at STP is obtained.The unknown alcohol is

A sample of 450 mg of unknown alcohol is added to CH_(3)MgBr when 168 of CH_(4) at STP is obtained the unknown alcohol is