How much faster than it's normal rate should the earth rotate about it's axis so that the weight of the body at the equator becomes zero `(R=6.4xx10^(6)m,g=9.8m//s^(2))` (in times)

How mcuh faster than its present rate should the earth rotate about its axis so that the weight of a body at the equator becomes zero? Also calculate the new length of the day. (c ) What would happen if rotation becomes faster ?

How many times faster than the present speed should the earth move to rotate about it’s axis, so that the apparent weight of the bodies on the equator becomes Zero.

How many times faster than its present speed the earth should rotate so that the apparent weight of an object at equator becomes zero ? Given radius of the earth = 6.37 xx 10^(6) m . What would be the duration of the day in that case ?

What is the time period of rotation of the earth around its axis so that the objects at the equator becomes weightless ? ( g = 9.8 m//s^(2) , Radius of earth= 6400 km)

What is the angular speed of rotation about its polar axis, so that the bodies on its equator would fell no weight? ( g=9.8 m//s^(2),R=6.4xx10^(6)m)

What is the time period of rotation of the earth around its axis so that the objects at the equator becomes weightless? ( g=9.8 m//s^2 , radius of the earth =6400km )

How much faster than its present speed should the. earth (radius 6.37 xx 10^(6)m ) rotate so that the bodies lying on the equator may fly off into space? (At equator, g=9.78m//s^(-2) )

How much faster than its present speed should the. earth (radius 6.37 xx 10^(6)m ) rotate so that the bodies lying on the equator may fly off into space? (At equator, g=9.78m//s^(-2) )