`0.45 g` of acid (mol. Wt.`=90`) was exactly neutralized by `20 ml` of `0.5(M) NaOH`.
The basicity of the given acid is

0.45 g of an acid ( mol. Mass = 90 ) is neutralised by 20 mol of 0.5 N NaOH solution. The basicity of the acid is :

0.45g of an acid of mol. Mass 90 was neutralised by 20mL of 0.5 N caustic potash (KOH) . The basicity of acid is :

0.45g of an acid of mol. Mass 90 was neutralised by 20mL of 0.54 N caustic potash (KOH) . The basicity of acid is :

0.45 gm of an acid with molecular mass 90 g/mole is neutralized by 20 ml of 0.5 N caustic potash. The basicity of the acid is :

0.3 g of an acid is neutralized by 40 cm^(3) of 0.125 N NaOH. Equivalent mass of the acid is

0.1092 g of a dibasic acid is exactly neutralized by 21cm^(3) of 0.1N NaOH. Calculate the molecular mass of the acid.