What will be the product, if `._(92)U^(235)` emits two `alpha`-and one `beta`-particle?

._(92)U^(235) undergoes successive disintegrations with the end product of ._(82)P^(203) . The number of alphaandbeta particles emitted are

""_(92)"U"^(235) undergoes successive disintegrations with the end product of ""_(82)"Pb"^(203) . The number of alpha and beta particles emitted are

""_(92)"U"^(235) undergoes successive disintegrations with the end product of ""_(82)"Pb"^(203) . The number of alpha and beta particles emitted are

A radioactive element ""_(92) X^(238) emits one alpha - particle and one beta ' particle in succession. What is the mass number of new element formed?

If ._(92)U^(235) assumed to decay only by emitting two alpha -and one beta -particles, the possible product of decays is

If ._(92)U^(235) assumed to decay only by emitting two alpha -and one beta -particles, the possible product of decays is

If it is assumed that ""_(92)^(235)U decays only by emitting alpha -and beta -particles, the possible product of the decay is :