At the mount of the tap area of cross-section is `2.0cm^(2)` and the speed of water is `3m//s`. The area of cross-section of the water column 80 cm below the tap is (use `g=10m//s^(2))`

In the previous question, at the mouth of the tap the area of cross-section is 2.5 cm^2 and the speed of water in 3 m//s . The area of cross-section of the water column 80 cm below the tap is.

Water from a tap emerges vertically downward with an initial speed of 1.0ms^(-1) . The cross-sectional area of the tap is 10^(-4) m^(2) . Assume that the flow is steady. What is the cross-sectional area of the stream 0.15 m below the tap? Use g=10 ms^(-2) .

Water from a tap of cross sectional area 1 cm^2 starts falling down vertically, with a speed of 1m//s . What is the area of cross section of the stream of water at a distance of 20cm below the mouth of the tap? [Assume that (1) the flow is steady, (2) pressure is constant throughout the stream of water and g= 10m//s^2 ]

The level of water in a tank is 5 m high. A hole of area of cross section 1 cm^(2) is made at the bottom of the tank. The rate of leakage of water for the hole in m^(3)s^(-1) is (g=10ms^(-2))

The level of water in a tank is 5 m high. A hole of area of cross section 1 cm^(2) is made at the bottom of the tank. The rate of leakage of water for the hole in m^(3)s^(-1) is (g=10ms^(-2))

Water is filled in a cylindrical container to a height of 3m . The ratio of the cross-sectional area of the orifice and the beaker is 0.1 . The square of the speed of the liquid coming out from the orifice is (g=10m//s^(2)) .

Water is filled in a cylindrical container to a height of 3m . The ratio of the cross-sectional area of the orifice and the beaker is 0.1 . The square of the speed of the liquid coming out from the orifice is (g=10m//s^(2)) .

Water is filled in a cylindrical container to a height of 3m . The ratio of the cross-sectional area of the orifice and the beaker is 0.1 . The square of the speed of the liquid coming out from the orifice is (g=10m//s^(2)) .