The shortest distance travelled by a particle executing SHM from mean position in 2 s is equal to `(sqrt(3)//2)` times its amplitude. Determine its time period.

The shortest distance travelled by a particle executing SHM form mean position in 2 seconds is equal to ( sqrt(3))/(2 ) times of its amplitude . Determine its time period .

A particle executes SHM from extreme position and covers a distance equal to half to its amplitude in 1 s. find out it's Time Period.

A particle executes SHM from extreme position and covers a distance equal to half to its amplitude in 1 s.

What is the total distance travelled by a body executing SHM in a time equal to its time period, if its amplitude is A?

The displacement from mean position of a particle in SHM at 3 seconds is sqrt(3) /2 of the amplitude. Its time period will be :

A particle execute S.H.M from the mean position. Its amplitude is A, its time period is .T.. At what displacement, its speed is half of its maximum speed.

The time period of a particle executing S.H.M.is 12 s. The shortest distance travelledby it from mean position in 2 second is ( amplitude is a )

The time period of a particle executing S.H.M.is 12 s. The shortest distance travelledby it from mean position in 2 second is ( amplitude is a )