" 10."4sqrt(-5)-1

sqrt(4sqrt(-5)-1)=

min[(x_1-x_2)^2+(5+sqrt(1-x_1^2)-sqrt(4x_2))^2],AAx_1,x_2 in R , is (a) 4sqrt(5)-1 (b) 3-2sqrt(2) (c) sqrt(5)+1 (d) sqrt(5)-1

(12)/(3+sqrt(5)+2sqrt(2)) is equal to 1-sqrt(5)+sqrt(2)+sqrt(10) (b) 1+sqrt(5)+sqrt(2)-sqrt(10) (c) 1+sqrt(5)-sqrt(2)+sqrt(10) (d) 1-sqrt(5)-sqrt(2)+sqrt(10)

The value of sin(pi/3-sin^(-1)(4/5)) is (a) (3sqrt(3)-4)/(10) (b) (3sqrt(3)+4)/(10) (c) (4sqrt(3)-3)/(10) (d) (4sqrt(3)+1)/(10)

The value of sin(pi/3-sin^(-1)(4/5)) is (a) (3sqrt(3)-4)/(10) (b) (3sqrt(3)+4)/(10) (c) (4sqrt(3)-3)/(10) (d) (4sqrt(3)+1)/(10)

Given x, y in R , x^(2) + y^(2) gt 0 . Then the range of (x^(2) + y^(2))/(x^(2) + xy + 4y^(2)) is (a) ((10 - 4 sqrt(5))/(3),(10 + 4 sqrt(5))/(3)) (b) ((10 - 4 sqrt(5))/(15),(10 + 4 sqrt(5))/(15)) (c) ((5- 4 sqrt(5))/(15),(5 + 4 sqrt(5))/(15)) (d) ((20- 4 sqrt(5))/(15),(20 + 4 sqrt(5))/(15))

min[(x_(1)-x_(2))^(2)+(3+sqrt(1-x_(1)^(2))-sqrt(4x_(2)))],AA x_(1),x_(2)in R is (a)4sqrt(5)+1 (b) 3-2sqrt(2)(c)sqrt(5)+1(d)sqrt(5)-1

min[(x_1-x_2)^2+(3+sqrt(1-x_1^2)-sqrt(4x_2))^2],AAx_1,x_2 in R , is (a) 4sqrt(5)+1 (b) 3-2sqrt(2) (c) sqrt(5)+1 (d) sqrt(5)-1

Find ( sqrt(5) + 1 )/( sqrt(5 ) - 1) = ( A ) ( 3 + sqrt(5) )/2 ( A ) ( 3 - sqrt(5) )/2 ( A ) ( 3 + sqrt(5) )/4 ( A ) ( 3 - sqrt(5) )/4