A cube of side a is placed in a uniform electric field `E = E_(0) hat(i) + E_(0) hat(j) + E_(0) k`. Total electric flux passing through the cube would be

A surface element vec(ds) = 5 hat(i) is placed in an electric field vec(E) = 4 hat(i) + 4 hat(j) + 4 hat(k) . What is the electric flux emanting from the surface ?

A surface element vec(ds) = 5 hat(i) is placed in an electric field vec(E) = 4 hat(i) + 4 hat(j) + 4 hat(k) . What is the electric flux emanting from the surface ?

A cube of length L is placed in a uniform electric field E. If two surfaces of the cube are perpendicular to E, then the total electric flux through the cube is—

A cube of side 1 is placed in a uniform field E, where E= E hat(i) . The net electric flux through the cube is

A cube of side l is p laced in a uniform field E, where E=E hati . The net electric flux through the cube is

The potential field of an electric field vec(E)=(y hat(i)+x hat(j)) is

The potential field of an electric field vec(E)=(y hat(i)+x hat(j)) is

The potential field of an electric field vec(E)=(y hat(i)+x hat(j)) is