Two like poles of strengths `m_(1)` and `m_(2)` are at far distance apart. The energy repuired to bring them `r_(0)` distance apart is

Two stationary particles of masses M_(1) and M_(2) are at a distance d apart. A third particle, lying on the line joining the particles experiences no resultant gravitational forces. What is the distance of this particle from M_(1) .

Two isolated point poles of strength 30 Am and 60 Am are placed a distance of 0.3 m.The force of repulsion is

Two bodies of masses M_(1) and M_(2) , are placed at a distance R apart. Then at the position where the gravitational field due to them is zero, the gravitational potential is

Particles of masses m_(1) and m_(2) are at a fixed distance apart. If the gravitational field strength at m_(1) and m_(2) are vecI_(1) and vecI_(2) respectively. Then

Two bodies of masses m_(1) and m_(2) ar placed at a distance r apart. Shows that the position where the gravitational field due to them is zer, the potential is given by V=-(G)/(r)"["m_(1)+m_(2)+2sqrt(m_(1)m_(2))"]"

Two bodies of masses m_(1) and m_(2) are placed at a distance r apart. Show that the position where the gravitational field due to them is zero, the potential is given by -G (m_(1) + m_(2) + 2 sqrt(m_(1) + m_(2)))//r