The compound interest on a certain sum is given by `C.I.=P(1+(R)/(100))^(n)-P`. Find C.I. when `P=rs1000,R=10%` P.a., and n=2.
The following steps are involved in solving the above problem. Arrange them in sequential order.
(A) `therefore C.I.=rs210`
(B) `1000((11)/(10))((11)/(10))-1000=1210-100`
(C) Given `Cl=P(1+(R)/(100))^(n)-P,P=rs1000`,
R=10% p.a., and n=2
(D) C.I. =`1000+(1+(10)/(100))^(2)-1000`