If `Delta ABC` is an isosceles triangle with `angle C=90^(@)` and AC=5 cm, then AB is

/_\ ABC is an isosceles triangle with /_C = 90^(@) and AC = 5 cm. Then, AB = ?

If Delta ABC is an isosceles triangle with hat(C ) = 90^(@) and AC = sqrt(8) cm then AB is :

∆ABC is an isosceles triangle in which /_C = 90° . If AC = 6 cm , Then AB is

ABC is an isosceles triangle in which angleACB=90^(@). If AC = 2 cm, then the value of AB is

ABC is an isosceles triangle in which angleACB=90^(@). If AC = 2 cm, then the value of AB is

Delta ABC is an isosceles triangle in which BC = 8 cm and AB = AC = 5 cm. Then, area of Delta ABC = …………….cm^(2) .