3),B=(2-3)" and "PA+PB=8

If A(3,0), B(-3,0) and PA+PB=10 then the equation of the locus of P is

Find the equation of Locus of P, if A (5,0), B(-5,0) and PA-PB= 8.

A(2, 3), B(2, -3) are two points. The equation to the locus of P such that PA+PB=8 is

A(2,3),B(2,-3) are two points.The equation to the locus of P. such that PA+PB=8

Let A-=(3,-4),B-=(1,2) . Let P-=(2k-1+1) be a variable point such that PA+PB is the minimum. Then k is

Through a given point P(5,2), secants are drawn to cut the circle x^(2)+y^(2)=25 at point A_(1)(B_(1)),A_(2)(B_(2)),A_(3)(B_(3)),A_(4)(B_(4)) and A_(5)(B_(5)) such that PA_(1)+PB_(1)=5,PA_(2)+PB_(2)=6,PA_(3)+PB_(3)=7,PA_(4)+PB_(4)=8 and PA_(5)+PB_(5)=9 find the value of

A (2, 3 ) , B ( 2, - 3 ) are two points. The equation to the locus of P such that PA + PB = 8 is

A(2,3) , B(-2,3) are two points.The locus of p which moves such that PA-PB=4 is