A parallel plate copacitor is first charged and then isolated, and a dielelctric slab is introduced between the plates. The quantity that remains unchanged is.

A parallel plate capacitor is first charged and then a dielectric slab is introduced between the plates. The quantity that remains unchanged is

A parallel plate capacitor is charged and then isolated. On increasing the plate separation

A parallel plate capacitor is charged and then isolated. On increasing the plate separation

A parallel plate capacitor is charged and then isolated. Now a dielectric slab is Introduced in it. Which of the following quantities will remain constant ?

C,V,U and Q are capacitance, potential difference, energy stored and charge of parallel plate capacitor respectively. The quantities that increase when a dielectric slab is introduced between the plates without discounting the battery are

Explain why the capacitance of a parallel plate capacitor increases when a dielectric slab is introduced between the plates.