(dy)/(dx)=(y(x+2y))/(x(2x+y))

Solve the differential equations: (dy)/(dx)=(y(2y-x))/(x(2y+x))

(dy)/(dx)=(y(2y-x))/(x(2y+x))=0 , given y=1, when x=1

Find the particular solution of the differential equation (dy)/(dx)=(y(2y-x))/(x(2y+x)) ,given that y=1 when x=1 .

If x ylog(x+y)=1 , prove that (dy)/(dx)=-(y(x^2y+x+y))/(x(x y^2+x+y))

(dy)/(dx)=(3x+2y)/(2x-3y)

x(dy)/(dx)+(y^(2))/(x)=y

The general solution of (dy)/(dx)=(2x-y)/(x+2y) is

Solve (dy)/(dx)=(x y)/(x^2+y^2), x^2+y^2 ne 0

If xy log(x+y)=1, prove that (dy)/(dx)=-(y(x^(2)y+x+y))/(x(xy^(2)+x+y))

xy log(x+y)=1, prove that (dy)/(dx)=-(y(x^(2)y+x+y))/(x(xy^(2)+x+y))