[" Two blocks of mass "m_(1)=6kg" and "m_(2)=3kg" are as shown in the "],[" diagram.Coefficient of friction between "m_(1)" and "m_(2)" and between "m_(1)],[[" and the surface is "0.5" and "0.4," respectively.The maximum "]],[" horizontal force that can be applied to the mass "m_(1)" so that they "],[" move without separation is (nearly) "]

Two blocks of mass m_(1) = 6 kg and m_(2) = 3kg are as shown in the diagram. Coefficient of friction between m_(1) and m_(2) and between m_(1) and m_(2) and between m_(1) and the surface is 0.5 and 0.4 , respectively . The maximum horizontal force that can be applied to the mass m_(1) so that they move without separation is

Two blocks a and B of mass m_(A)=1kg and m_(B)=3kg are kept on the table as shown in figure the coefficient of friction between A and B is 0.2 and between B and the surface of the table is also 0.2 the maximum force F that can be applied on B horizontally, so that the block A does not slide over the block B is [Take g=10m//s^(2) ]

Two blocks m_(1)=1kg , m_(2)=2kg are placed one upon the other. m_(1) is kept on m_(2) . The force of static friction between m_(1) and m_(2) is 0.2 and between m_(2) and the horizontal surface and the floor is 0.28 . Calculate the maximum force that can be applied on m_(2) so that m_(1) and m_(2) does not get separated. (g=10ms^(-2))

Two blocks A and B of masses m_(A) = 1kg and m_(B) = 3kg are kept on the table as shown in figure. The coefficient of friction between A and B is 0.2 and between B and the surface of the table is also 0.2. The maximum force F that can be applied on B horizontally, so that the block A does not slide over the block B is ________ (in N): [Take g = 10 m//s^(2) ]

A block of mass m is placed on another block of mass M which itself is lying on a horizontal surface .The coefficient of friction between two blocks is mu_(1) and that between the block of mass M and horizontal surfece is mu_(2) What maximum horizontal force can be applied to the lower block move without separation?

A block of mass m is placed on another block of mass M which itself is lying on a horizontal surface .The coefficient of friction between two blocks is mu_(1) and that between the block of mass M and horizontal surfece is mu_(2) What maximum horizontal force can be applied to the lower block move without separation?

Two block of masses m_(1) and m_(2) connected by a light spring rest on a horizontal plane. The coefficient of friction between the block and the surface is equal to mu . What minimum constant force has to be applied in the horizontal direction to the block of mass m_(1) in order to shift the other block?

Two blocks of masses m_(1) = 10 kg and m_(2) = 20 kg are connected by a spring of stiffness k = 200 N/m. The coefficient of friction between the blocks and the fixed horizontal surface is mu = 0.1 . Find the minimum constant horizontal force F (in Newton) to be applied to m1 in order to slide the mass m_(2) . (Take g = 10 m//s^(2) )

Two blocks of masses m_(1) = 10 kg and m_(2) = 20 kg are connected by a spring of stiffness k = 200 N/m. The coefficient of friction between the blocks and the fixed horizontal surface is mu = 0.1 . Find the minimum constant horizontal force F (in Newton) to be applied to m1 in order to slide the mass m_(2) . (Take g = 10 m//s^(2) )