A bus begins to move with an acceleration of ` 1 ms^(-1)` . A man who is `1 48m` behind the bus starts running at ` 10 ms^(-1)` to catch the bus, the man will be able to catch the bus after .

A bus starts from rest with an acceleration of 1 m//s^(2) A man who is 48 m behind the bus starts with a uniform velocity of 10 m s^(-1) . Then after how much time the man will catch the bus ?

A bus starts moving with 1 ms^(-2) acceleration. A man 48 m away from bus starts moving with 10 ms to catch the bus, then man will reach to bus after ........

A bus starts moving with an acceleration2 ms? A cyclist 96 m behind the bus starts simultaneously towards the bus at 20 m s-, after what time will he able to overtake the bus?

A bus starts moving with acceleration of 2m/s^2 . A cyclist 96m behind the bus starts simultaneously towards the bus at 20m/s . After what time will he be able to overtake the bus ?

A man is at a distance of 6 m from a bus. The bus begins to move with a constant acceleration of 3 ms^(−2) . In order to catch the bus, the minimum speed with which the man should run towards the bus is

A man is at a distance of 6 m from a bus. The bus begins to move with a constant acceleration of 3 ms^(−2) . In order to catch the bus, the minimum speed with which the man should run towards the bus is

A bus is beginning to move with aceleratino of 1 ms^-2 . A man wo wants to board it can run at 9 ms^-1 . Show that he3 can catch it in 8 sec., if he is 40 m behind when it starts.