The position vector of a particle is given by `vec r = (2t hati+5t^(2)hatj)m` (t is time in sec). Then the angle between initial velocity and initial acceleration is

The position of a particle is given by vecr=3.0t (hati)+2.0t^2(hatj)+5.0hatk .where t is in seconds and r is in meters Find the velocity and acceleration of the particle in magnitude and direction at time t=3 sec.

The position vector of a particle is given by vecr=(3t^(2)hati+4t^(2)hatj+7hatk)m at a given time t .The net displacement of the particle after 10 s is

If the position vector of the particle is given by vecr = 3 t^2 hati + 5t hatj + 4hatk . Find the velocity of the particle at t = 3s.

The position of a particle is given by vec r =(8 t hati +3t^(2) +5 hatk) m where t is measured in second and vec r in meter. Calculate, the magnitude of velocity at t = 5 s,

The position of a particle is given by vec r =(8 t hati +3t^(2) +5 hatk) m where t is measured in second and vec r in meter. Calculate, the magnitude of velocity at t = 5 s,

The position vector of a particle is given by r = 3t^(2)hati + 4t^(2)hatj + 7hatk m at a given time 't'. The net displacement of the particle after 10s is

The position vector of a particle is given by vecr=(2 sin 2t)hati+(3+ cos 2t)hatj+(8t)hatk . Determine its velocity and acceleration at t=pi//3 .

The position vector of the particle is vecr=3t^2 hati+5t hatj+9hatk . What is the acceleration of the particle?

The position vector of a aprticle is given as vecr=(5t^2-4t+6)hati+(t^2)hatj . The time after which the velocity vector and acceleration vector becomes perpendicular to each other is equal to

The position vector of a aprticle is given as vecr=(3t^2-2t+5)hati+(3t^2)hatj . The time after which the velocity vector and acceleration vector becomes perpendicular to each other is equal to