4" (sex "A-cos A)(cot A+tan A)=sec A tan A

(sec A-cos A)(cot A+tan A)=tan A.sec A

(sec A - cos A) (cot A + tan A) = tan A sec A.

cos A(sec A-cos A)(cot A+tan A) =?

7. (sin A+cos A)(cot A+tan A)=sec A+cosec A

Prove the following identity: (tan A)/(1-cot A)+(cot A)/(tan A)=(sec A cos ecA+1)

Prove: (sec A-cos ecA)(1+tan A+cot A)=tan A sec A-cot A cos ecA

(tan A) / (1-cot A) + (cot A) / (1-tan A) = 1 + tan A + cot A = 1 + sec A cos ecA

Prove that (i) (tan A+ sin A)/(tan A- sin A)= (sec A+1)/(sec A-1) (ii) (cot A- cos A)/(cot A+ cos A)= ("cosec" A-1)/("cosec" A+1)

(tan A) / (1-cot A) + (cot A) / (1-tan A) = 1 + tan A + cot A = 1 + sec A cos ecA (1 + cos theta + sin theta) / (1 + cos theta-sin theta) = (1 + sin theta) / (cos theta)