[" 11."ABC" and "ADC" are two right triangles with common hypotenuse "AC" .Prove that "],[/_CAD=/_CBD" ."]

ABC and ADC are two right triangle with common hypotenuse AC. Prove that CAD = CBD.

A B C and A D C are two right triangles with common hypotenuse A Cdot Prove that /_C A D=/_C B Ddot

A B C and A D C are two right triangles with common hypotenuse A Cdot Prove that /_C A D=/_C B Ddot

A B C and A D C are two right triangles with common hypotenuse A Cdot Prove that /_C A D=/_C B Ddot

ABC and ADC are two right triangles with common hypotenuse AC. Prove that angle CAD = angle CBD.

ABC and DBC are two right angled triangles with common hypotenuse BC with their sides AC and BD intersecting at P. Prove that: AP×PC=DP×PB .

In the given figure, triangles ABC and DCB are right angled at A and D respectively and AC = DB. Prove that /_\ ABC = /_\ DCB .

ABC is an isosceles right triangle right- angled at C. Prove that AB^(2)=2AC^(2)

If BD is the perpendicular drawn from the vertex B of the right triangle ABC to the hypotenuse AC,prove that(iii) BC^2=CDxxAC

In right angled triangle ABC , /_A is a right angle. AD is perpendicular on the hypotenuse BC . Prove that (DeltaABC)/(DeltaACD)=(BC^(2))/(AC^(2)) .