cos theta+sin2 theta+cos3 theta=0

Simplify: (sin8 theta cos theta-sin6 theta cos3 theta)/(cos2 theta cos theta-sin3 theta sin4 theta)

Simplify: (sin^(3) theta + cos^(3) theta)/(sin theta + cos theta) + sin theta cos theta

The value of (2(sin2 theta+2cos^(2)theta-1))/(cos theta-sin theta-cos3 theta+sin3 theta)=

The value of (2 (sin2 theta-2 cos^(2)theta-1))/(cos theta-sin theta-cos 3 theta +sin 3 theta)=

If sin theta+sin2 theta+sin3 theta=sin alpha and cos theta+cos2 theta+cos3 theta=cos alpha, then theta is equal to

sin theta+sin2 theta+sin3 theta=sin alpha and cos theta+cos2 theta+cos3 theta=cos alpha then theta is equal to

3. sin^(3)theta+cos^(3)theta=(sin theta+cos theta)(1-sin theta cos theta)

(sin theta+cos theta)(1-sin theta cos theta)=sin^3 theta+cos^3 theta

Prove that: (sin^(3) theta + cos^(3) theta)/(sin theta + cos theta) = 1-sin theta cos theta

Prove that (cos^3theta+sin^3 theta)/(cos theta+sin theta)+(cos^3 theta-sin^3 theta)/(cos theta-sin theta)=2