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3x+ax=10" an "2x-2y=2...

3x+ax=10" an "2x-2y=2

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Using substitution method solve for x and y : 3x+5y=10 and 2x-y=2 .

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x+7y=10 3x-2y=7

The equation of the ellipse whose axes are coincident with the coordinates axes and which touches the straight lines 3x-2y-20=0 and x+6y-20=0 is (x^2)/(40)+(y^2)/(10)=1 (b) (x^2)/5+(y^2)/8=1 (x^2)/(10)+(y^2)/(40)=1 (d) (x^2)/(40)+(y^2)/(30)=1

The equation of the ellipse whose axes are coincident with the coordinates axes and which touches the straight lines 3x-2y-20=0 and x+6y-20=0 is (x^(2))/(40)+(y^(2))/(10)=1( b) (x^(2))/(5)+(y^(2))/(8)=1(x^(2))/(10)+(y^(2))/(40)=1 (d) (x^(2))/(40)+(y^(2))/(30)=1