5quad 4z+3=6+2zquad .4

If x=4z^(2)+5,quad y=6z^(2)+7z+3, find (d^(2)y)/(dx^(2))

The planes 2x - y + 4z = 3 and 5x - 2.5y + 10z = 6 are :

The plane 2x - y + 4z = 5 and 5x - (2.5) y + 10 z =6 are

If the complex numbers z_1 , z_2, z_3 and z_4 denote the vertices of a square taken in order. If z_1 = 3+4i and z_3 = 5+ 6i , then the other two vertices z_2 and z_4 are respectively a) 5+4i, 5+6i b) 5+4i, 3+6i c) 5+6i, 3+5i d) 3+6i, 5+3i

Divide: 5x^3-15 x^2+25 x\ b y\ 5x 4z^3+6z^2-z\ b y-1/2z

The system of equations x+2y +3z =4, 2x+3y+4z=5,3x+4y+5z=6 has

The values of x, y, z for the equations 5x-y+4z=5, 2x+3y+5z=2, 5x-2y+6z=1 are

If x=4z^(2)+5 and y=6z^(2)+7z+3 , then find (d^(2)y)/(dx^(2))

4x + 3y + 2z =1 x-y + 3z = 4 2x + 5y - 4z = 6 has n solution than n =