[" drif "],[" The number of free electrons in a wire is "2times10^(28)/m^(3)" .Drift velocity of the electrons is "1.0cm/s" in "],[" 810.The wire.Calculate current density in the wire."]

Free electron number density in one wire is n, its area of cross-section is A, and drift velocit of electrons is v_(d) Then electric current forme in this wire is ......

The magnitude of current density in a copper wire is 500 A//cm^2 . If the number of free electrons per cm^3 of copper is 8.47 xx 10^22 , calculate the drift velocity of the electrons through the copper wire (charge on an e = 1.6 xx 10^-19 C).

Electron density in a conductor of area of cross section 0.006 cm^2 is 8.0 xx10^(22) cm ^(-3) . Calculate the drift velocity of electron in the wire if a current of 2 flows through it.

In copper the number of free electrons per m^(3) is 8.4 x 10^(28). Calculate the drift velocity of electrons in a copper wire of cross sectional area 2 x 10^(-6)m^(2), if a current of 0.63A is flowing through it.

A Cu wire of cross sectional area 1mm^2 is carying current 0.21A. What is the drift velocity of the free ejectrons in the wire?. Electron density of Cu = 8.4xx10^28/m^3 .