[" The radical centre of the circles "x^(2)+y^(2)=1],[x^(2)+y^(2)-2x-3=0" and "x^(2)+y^(2)-2y-3=0" is "]

The radical centre of the circles x^(2) + y^(2) +1=0 , x^(2) + y^(2) - 2x - 3 = 0 " and " x^(2) + y^(2) - 2y - 3 = 0 is

" The radical centre of the circles "x^(2)+y^(2)-x+3y-3=0,x^(2)+y^(2)-2x+2y-2=0,x^(2)+y^(2)+2x+3y-

The radical centre of the circles x^(2) + y^(2) = 1 , x^(2) + y^(2) - 2x = 1 , x^(2) + y^(2) - 2y = 1 is

The radical centre of the circles x^(2)+y^(2)=9 , x^(2)+y^(2)-2x-2y-5=0 , x^(2)+y^(2)+4x+6y-19=0 is A) (0,0) (B) (1,1) (C) (2,2) (D) (3,3)

Coordinates of the centre of the circle which bisects the circumferences of the circles x^(2)+y^(2)=1;x^(2)+y^(2)+2x-3=0 and x^(2)+y^(2)+2y-3=0 is

Find the radical centre of the circles x^(2)+y^(2)+4x=7=0, 2x^(2)+2y^(2)+3x+5y-9=0 and x^(2)+y^(2)+y=0.

Find the radical centre of circles x^(2)+y^(2)+3x+2y+1=0,x^(2)+y^(2)-x+6y+5=0 and x^(2)+y^(2)+5x-8y+15=0 . Also find the equation of the circle cutting them orthogonally.

if the radical centre of the three circles x^(2)+y^(2)-2x-1=0 and x^(2)+y^(2)-3y=1 and 2x^(2)+2y^(2)-x-7y-2=0 is Q then Q_(x)+Q_(y) is